Nette\Database\Structure::getHasManyReference PHP Method

    public function getHasManyReference($table, $targetTable = NULL)
    {
        $this->needStructure();
        $table = $this->resolveFQTableName($table);
        if ($targetTable) {
            $targetTable = $this->resolveFQTableName($targetTable);
            foreach ($this->structure['hasMany'][$table] as $key => $value) {
                if (strtolower($key) === $targetTable) {
                    return $this->structure['hasMany'][$table][$key];
                }
            }
            return NULL;
        } else {
            if (!isset($this->structure['hasMany'][$table])) {
                return [];
            }
            return $this->structure['hasMany'][$table];
        }
    }