mageekguy\atoum\asserters\phpResource::isOfType PHP Method

    public function isOfType($type, $failMessage = null)
    {
        $actualType = get_resource_type($this->valueIsSet()->value);
        if ($actualType === $type) {
            $this->pass();
        } else {
            $this->fail($failMessage ?: $this->_('%s is not of type %s', $this, $type));
        }
        return $this;
    }