Symfony\Component\Console\Formatter\OutputFormatter::hasStyle PHP Method

hasStyle() public method

Checks if output formatter has style with specified name.
public hasStyle ( string $name ) : boolean
$name string
return boolean
    public function hasStyle($name)
    {
        return isset($this->styles[strtolower($name)]);
    }

Usage Example

コード例 #1
0
 public function testNotDecoratedFormatter()
 {
     $formatter = new OutputFormatter(false);
     $this->assertTrue($formatter->hasStyle('error'));
     $this->assertTrue($formatter->hasStyle('info'));
     $this->assertTrue($formatter->hasStyle('comment'));
     $this->assertTrue($formatter->hasStyle('question'));
     $this->assertEquals("some error", $formatter->format('<error>some error</error>'));
     $this->assertEquals("some info", $formatter->format('<info>some info</info>'));
     $this->assertEquals("some comment", $formatter->format('<comment>some comment</comment>'));
     $this->assertEquals("some question", $formatter->format('<question>some question</question>'));
     $formatter->setDecorated(true);
     $this->assertEquals("some error", $formatter->format('<error>some error</error>'));
     $this->assertEquals("some info", $formatter->format('<info>some info</info>'));
     $this->assertEquals("some comment", $formatter->format('<comment>some comment</comment>'));
     $this->assertEquals("some question", $formatter->format('<question>some question</question>'));
 }