think\console\input\Definition::hasArgument PHP Method

    public function hasArgument($name)
    {
        $arguments = is_int($name) ? array_values($this->arguments) : $this->arguments;
        return isset($arguments[$name]);
    }

 /**
  * 检查是否存在某个参数
  * @param string|int $name 参数名或位置
  * @return bool
  */
 public function hasArgument($name)
 {
     return $this->definition->hasArgument($name);
 }