Drivers\Abstraction\Sql::from PHP Метод

from() публичный Метод

..FROM ... " statement.
public from ( ) : object
Результат object
    public function from()
    {
        $tables = func_get_args();
        if (is_array($tables[0])) {
            $tables = $tables[0];
        }
        $this->tables = $tables;
        return $this;
    }