public function test_it_should_sum_all_from_one_list_with_single_element()
{
// sum <$> [1, 2] <*> [4, 5]
$sum = f\curryN(2, 'example\\sum');
$a = Listt::of([1, 2]);
$b = Listt::of([4, 5]);
$result = f\map($sum, $a)->ap($b);
$this->assertEquals(Listt::of([5, 6, 6, 7]), $result);
}