Flake\Util\Frameworks::getPath PHP Метод

    function getPath($sName)
    {
        if (self::isAFramework($sName)) {
            throw new \Flake\Core\Exception(htmlspecialchars(${$sName}) . " is not a framework.", $sName);
        }
        return \Flake\Util\Tools::appendSlash(PROJECT_PATH_FRAMEWORKS . $sName);
    }