Google\Cloud\Dev\Snippet\Parser\Snippet::replace PHP Метод

replace() публичный Метод

Hopefully this is obvious, but be careful using this, and only use it when no other feasible options present themselves. It's pretty easy to make your test useless when you're modifying the thing you are trying to test. This is provided for cases when a snippet relies on a global, or on something else which can not be overridden or mocked.

public replace ( string $old, string $new ) : void
$old	string	The string to be replaced.
$new	string	The new string to insert.
Результат	void