Prado\I18N\core\DateFormat::getYear PHP Метод

    protected function getYear($date, $pattern = 'yyyy')
    {
        $year = $date['year'];
        switch ($pattern) {
            case 'yy':
                return substr($year, 2);
            case 'yyyy':
                return $year;
            default:
                throw new Exception('The pattern for year is either "yy" or "yyyy".');
        }
    }